Calling Mysql Iteratively and Passing Parameters from Bash Loop

Below we see an example of calling a mysql script from a file and passing a param.

sql script

So make a file with the following (or whatever else you wish):

SET @i = 1;
use databaseName;
SET @pID=@i+100;
SET @partnerID=concat('partner',@pID);
select @i, @pID , @partnerID;

Now, this will print out the values of i, pID, and partnerID.
Below that you could include insert statements or whatever else you wish.

Now how do we call this from bash and set the @i param?

bash script

user=root
password=mysqlPass
database=db

for i in {300..400..5}
do
sed -i "1 s/.*/set @i=$i;/" sample.sql
mysql --user="$user" --password="$password" < sample.sql
done

So how does this work?
We use sed to replace the first line completely in sample.sql with a new “set @i=” command containing the i param we want.
We then call mysql and feed the rewritten file.

Another way to do this would be to concatenate the sample.sql contents to the set command, and feed them to mysql in memory.

Menelaos Bakopoulos

Mr. Menelaos Bakopoulos is currently pursuing his PhD both at Center for TeleInFrastruktur (CTiF) at Aalborg University (AAU) in Denmark and Athens Information Technology (AIT) in Athens, Greece. He received a Master in Information Technology and Telecommunications Systems from Athens Information Technology and a B.Sc. in Computer Science & Management Information Systems from the American College of Thessaloniki. Since April 2008 he has been a member of the Multimedia, Knowledge, and Web Technologies Group.

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